# The length of a rectangle is 12 inches more than its width. What is the width of the rectangle if the perimeter is 42 inches?

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Let ( w ) represent the width of the rectangle.

Given that the length of the rectangle is 12 inches more than its width, the length can be expressed as ( w + 12 ) inches.

The perimeter of a rectangle is given by the formula: ( P = 2(w + l) ), where ( P ) is the perimeter, ( w ) is the width, and ( l ) is the length.

We are given that the perimeter is 42 inches, so we have the equation: [ 42 = 2(w + w + 12) ]

Solve for ( w ) to find the width of the rectangle.

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Let the width of the rectangle be represented by ( w ) inches.

Given that the length is 12 inches more than its width, we can express the length as ( w + 12 ) inches.

The perimeter of a rectangle is given by the formula ( 2 \times ( \text{length} + \text{width} ) ).

Substituting the given values into the formula for perimeter:

( 2 \times ( w + (w + 12) ) = 42 )

Solve for ( w ):

( 2 \times ( 2w + 12 ) = 42 )

( 4w + 24 = 42 )

( 4w = 42 - 24 )

( 4w = 18 )

( w = \frac{18}{4} )

( w = 4.5 )

The width of the rectangle is 4.5 inches.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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