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The interior angles of a hexagon are #x+2, x-8, x +7, x -3, x+6, and x -4#. What is the value of #x#?

Answer 1

Savannah Aguilar

#x=120#

#"the "color(blue)"sum of the interior angles of a polygon"# is.

#•color(white)(x)"sum "=180^@(n-2)#

#"where n is the number of sides"#

#"for a hexagon "n=6#

#"sum "=180^@xx4=720^@#

#"sum the 6 given angles and equate to 720"#

#x+2+x-8+x+7+x-3+x+6+x-4=720#

#6x=720rArrx=720/6=120#

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Answer 2

Sadie Adams

To find the value of ( x ), you need to sum up the interior angles of the hexagon and set the sum equal to ( 180^\circ ) since the sum of interior angles of a polygon with ( n ) sides is given by ( (n-2) \times 180^\circ ).

Sum of the interior angles of a hexagon ( = (6-2) \times 180^\circ = 720^\circ ).

So, ( (x+2) + (x-8) + (x+7) + (x-3) + (x+6) + (x-4) = 720^\circ ).

Solve this equation for ( x ).

( 6x - 2 = 720^\circ )

( 6x = 722^\circ )

( x = \frac{722^\circ}{6} )

( x = 120.33^\circ )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.