# The cost function for a product is C(x)=0.8x^2 +120x+110. How to find average cost over [0,600] ?

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The average price during this time frame can be found by

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To find the average cost over the interval [0, 600], you need to divide the total cost by the total quantity produced over that interval. The total cost is the integral of the cost function C(x) over the interval [0, 600], and the total quantity produced is 600 units.

First, find the integral of the cost function C(x) over the interval [0, 600]:

∫[0,600] C(x) dx = ∫[0,600] (0.8x^2 + 120x + 110) dx

Then, evaluate this integral:

∫[0,600] (0.8x^2 + 120x + 110) dx = [0.8*(1/3)*x^3 + 120*(1/2)*x^2 + 110*x] evaluated from x = 0 to x = 600

= 0.8*(1/3)*600^3 + 120*(1/2)*600^2 + 110*600 - 0.8*(1/3)*0^3 - 120*(1/2)*0^2 - 110*0

= (0.8*(1/3)*600^3 + 120*(1/2)*600^2 + 110*600)

Then, divide the total cost by the total quantity produced:

Average Cost = Total Cost / Total Quantity Produced

= [(0.8*(1/3)*600^3 + 120*(1/2)*600^2 + 110*600)] / 600

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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