The height of an open box is 1 cm more than the length of a side of its square base. if the open box has a surface area of 96 cm (squared), how do you find the dimensions.?

Answer 1

Savannah Anderson

The dimensions of the box would be length= width = 4cms and height = 5 cms

Let the side of the square base be x cms, then height would be x+1 cms.

Surface area of the open box, would be area of the base and area of its four faces, =xx +4x*(x+1)

Therefore #x^2 +4x^2 +4x=96#

#5x^2 +4x -96=0#

#5x^2 +24x-20x-96=0#

#x(5x+24) -4(5x+24)=0# #(x-4)(5x+24)=0#. Reject negative value for x, hence x= 4 cms

The dimensions of the box would be length= width = 4cms and height = 5 cms

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Answer 2

Isaiah Anthony

You'll find #4cm and 5 cm#

Call the length of the side of the square base #x#:

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.