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The heat of vaporization of water is 540 cal/g. How many calories would be needed to convert 3 moles of water to vapor?

Answer 1

Mateo Aguilar

#Q=3*molxx18.01*g*mol^-1xx540*cal*g^-1#

#~=# #2500*cal#

Note that here we consider the enthalpy of vaporization ONLY.

Both the water and the steam are considered to be at #100# #""^@C#.

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Answer 2

Wyatt Atkins

To calculate the number of calories needed to convert 3 moles of water to vapor, you would use the heat of vaporization of water, which is 540 cal/g. First, you need to determine the mass of 3 moles of water, which is equal to the molar mass of water (18.015 g/mol) multiplied by the number of moles (3 mol). Then, you would multiply the mass by the heat of vaporization to find the total number of calories needed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.