The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #35 ^o K#. If the temperature of the gas changes to #80 ^oK#, what is the new pressure of the gas?
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Xavier AdameTo find the new pressure, use the formula: P1/T1 = P2/T2
Given: P1 = 9 Pa T1 = 35 K T2 = 80 K
Substitute the values: 9/35 = P2/80
Solve for P2: P2 = (9/35) * 80
P2 ≈ 20.57 Pa
So, the new pressure of the gas is approximately 20.57 Pa.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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