# The gas inside of a container exerts #9 Pa# of pressure and is at a temperature of #190 ^o K#. If the pressure in the container changes to #34 Pa# with no change in the container's volume, what is the new temperature of the gas?

The temperature is

We apply Gay Lussac's Law

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Use the combined gas law: ( P_1/T_1 = P_2/T_2 ) Rearrange the equation to solve for ( T_2 ): ( T_2 = (P_2 * T_1) / P_1 ) Substitute values: ( T_2 = (34 * 190) / 9 ) Calculate: ( T_2 \approx 721.11 , K )

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