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The gas inside of a container exerts #8 Pa# of pressure and is at a temperature of #210 ^o K#. If the temperature of the gas changes to #35 ^oC# with no change in the container's volume, what is the new pressure of the gas?

Answer 1

Layla Ahmed

#P_f=11.73" "Pa#

#P_i=8" "Pa" initial pressure"#

#T_1=210" "^o K" initial temperature"#

#T_2=35" "^o C" ; "T_2=35+273=308 " "^o K#

#P_f=?" final pressure"#

#P_i/T_i=P_f/T_f#

#8/210=P_f/308#

#P_f=(8*308)/210#

#P_f=11.73" "Pa#

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Answer 2

Adrian Ayala

To find the new pressure of the gas, we can use the ideal gas law:

[ P_1 \times V_1 / T_1 = P_2 \times V_2 / T_2 ]

Given that the volume remains constant, we can simplify the equation to:

[ P_1 / T_1 = P_2 / T_2 ]

Plugging in

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.