The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #450 ^o K#. If the pressure in the container changes to #16 Pa# with no change in the container's volume, what is the new temperature of the gas?

Answer 1

#"The new temperature of gas :"480 ^o K#

#P_i:"The initial pressure of gas"# #P_l:"The last pressure of gas"# #T_i:"The initial temperature of gas"# #T_l:"The last temperature of gas"# #"Let us use the formula below"#

#P_i/T_i=P_l/T_l#

#"Plug the given values into equation"#

#P_i=15Pa# #P_l=16Pa#

#T_i=450 ^o K# #T_f=?#

#15/450=16/T_f#

#15*T_f=16*450#

#T_f=(16*450)/15#

#T_f=480^o K#

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Answer 2

Xavier Adame

The new temperature of the gas is approximately 473.44 K.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.