The gas inside of a container exerts #15 Pa# of pressure and is at a temperature of #450 ^o K#. If the pressure in the container changes to #36 Pa# with no change in the container's volume, what is the new temperature of the gas?

Answer 1

The new temperature is #=1080K#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#
The initial pressure is #P_1=15Pa#
The initial temperature is #T_1=450K#
The final pressure is #P_2=36Pa#

The final temperature is

#T_2=P_2/P_1*T_1#
#=36/15*450#
#=1080K#
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Answer 2

The new temperature of the gas is 1080 K.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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