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The gas inside of a container exerts #12 Pa# of pressure and is at a temperature of #85 ^o K#. If the temperature of the gas changes to #60 ^oK# with no change in the container's volume, what is the new pressure of the gas?

Answer 1

William Audy

The new pressure is #=8.47Pa#

Incorporate Gay Lussac's Law, which

#P_1/T_1=P_2/T_2#, at constant volume

The initial pressure is #P_1=12Pa#

The initial temperature is #T_1=85K#

The final temperature is #T_2=60K#

The last bit of pressure is

#P_2=T_2/T_1*P_1=60/85*12=8.47Pa#

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Answer 2

Adam Arnold

The new pressure of the gas is approximately 8 Pa.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.