The gas in a container is at a pressure of 3.00 atm at 25°C. Directions on the container wam the user not to keep it in a place where the temperature exceeds 52°C. What would the gas pressure in the container be at 52°C?

Answer 1

The pressure is #=3.27atm#

We apply Gay Lussac's Law

#P_1/T_1=P_2/T_2#
The initial pressure, #P_1=3.00atm#
The initial temperature #T_1=25+273=298K#
The final temperature #T_2=52+273=325K#

The final pressure is

#P_2=T_2/T_1*P_1#
#=325/298*3=3.27atm#
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Answer 2

The gas pressure in the container would be approximately 3.73 atm at 52°C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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