The formula for the illegal drug cocaine is #C_17H_21NO_4#, which is 303.39 g/mol. What is the percentage of carbon in the compound?
Approx. 70%
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In order to determine the percentage of carbon present in the compound, we must first compute the molar mass of carbon (C) and divide it by the total molar mass of the compound (303.39 g/mol). The resulting percentage of carbon is then expressed as follows: percentage of carbon = (12.01 g/mol / 303.39 g/mol) * 100 ≈ 3.96%. The percentage of carbon in the compound cocaine is thus approximately 3.96%.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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