# The footfall player has a mass equal to 100kg standing on earth surface at distance of 6.38×10^6m.calculate force of gravitational attraction between the earth and football player?

Applying the universal gravitational law of Newton:

Given two masses' respective masses and their proximity to one another, we can find the attraction force between them.

Let's now enter everything into the formula:

The gravitational field strength, or force per unit mass, can be found using the following equation:

In light of our value:

Thus, it appears to be in order.

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The force of gravitational attraction between the Earth and the football player can be calculated using Newton's law of universal gravitation formula:

F = (G * m1 * m2) / r^2

Where: F = force of gravitational attraction G = gravitational constant (6.674 × 10^-11 N*m^2/kg^2) m1 = mass of the Earth (5.972 × 10^24 kg) m2 = mass of the football player (100 kg) r = distance between the centers of mass of the Earth and the football player (6.38 × 10^6 m)

Plugging in the values:

F = (6.674 × 10^-11 * 5.972 × 10^24 * 100) / (6.38 × 10^6)^2

F ≈ (6.674 × 10^-11 * 5.972 × 10^26) / (4.0684 × 10^13)

F ≈ 9.81 N

So, the force of gravitational attraction between the Earth and the football player is approximately 9.81 Newtons.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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