The elements A and Z combine to produce two different compounds: #A_2Z_3# and #AZ_2#. If 0.15 mole of #A_2Z_3# has a mass of 15.9 g and 0.15 mole of #AZ_2# has a mass of 9.3 g, what are the atomic masses of A and Z?

Answer 1

#m_"a A" = "26 u"#

#m_"a Z" = "18 u"#

All you have to do here is set up a system of two equations with two unknowns, the molar mass of #"A"# and the molar mass of #"Z"#.

Once you know the molar masses of the two elements, you can use a simple conversion factor to find their respective atomic masses.

So, you know that #0.15# moles of #"A"_2"Z"_3# have a mass of #"15.9 g"#. To make the calculations easier, calculate the mass of one mole of #"A"_2"Z"_3#
#1 color(red)(cancel(color(black)("mole A"_2"Z"_3))) * "15.9 g"/(0.15color(red)(cancel(color(black)("moles A"_2"Z"_3)))) = "106 g"#
Notice that one mole of #"A"_2"Z"_3# contains
If you take #a# to be the molar mass of #"A"# and #z# to be the molar mass of #"Z"#, you can say that
#2 * a + 3 * z = "106 g"" " " "color(orange)((1))#
Now do the same for #"AZ"_2#. You have
#1 color(red)(cancel(color(black)("mole AZ"_2))) * "9.3 g"/(0.15color(red)(cancel(color(black)("moles AZ"_2)))) = "62 g"#
This time, in one mole of #"AZ"_2# you have

You will thus have

#a + 2 * z = "62 g"" " " "color(orange)((2))#
Use equation #color(orange)((2))# to write
#a = 62 - 2z#
Plug this into equation #color(orange)((1))# to get
#2 * (62 - 2z) + 3 * z= 106#
#124 - 4z + 3z = 106#

Rearrange to find

#z = 18#

This means that you have

#a = 62 - 2 * 18 = 26#

So, you know that the molar masses of the two elements are

#"For A: " "26 g mol"^(-1)#
#"For B: " "18 g mol"^(-1)#

To convert these to atomic masses, use the conversion factor

#color(purple)(bar(ul(|color(white)(a/a)color(black)("1 u " = " 1 g mol"^(-1))color(white)(a/a)|)))#

You will have

#"For A: " m_"a A" = "26 u"#
#"For B: " m_"a Z" = "18 u"#
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Answer 2

The atomic mass of A is 7.0 g/mol, and the atomic mass of Z is 6.0 g/mol.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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