The density of a sample of aluminum is 2.70 g/cm3. You submerse a sample of aluminum in water, and the volume of the water rises 1.3 L (1.3 L is displaced by the aluminum). Using the correct number of significant figures, what is the mass of the sample?

Question

Henry Antrim · Accepted Answer

The mass of aluminum is 3500 g, rounded to two significant figures.

Mass per unit of volume is called density. #"density"="mass"/"volume"# The volume of the aluminum sample is equal to the displaced volume of water. Since the given density is in #"g/cm"^3#, the unit for the volume of water needs to be converted to #"cm"^3#. #"1 L=1000 mL"# #"1 mL=1 cm"^3"# #1.3cancel"L"xx(1000cancel"mL")/(1cancel"L")xx(1"cm"^3)/(1cancel"mL")="1300 cm"^3"# In order to determine the mass of an object when its density and volume are known, the equation needs to be rearranged to isolate #"mass"# #"mass"="density"xx"volume"# Enter the specified density and volume into the formula and find the solution. #"mass"=2.70"g"/cancel"cm"^3xx1300cancel"cm"^3"=3510 g"=3500 "g"# rounded to two significant figures

Mateo Aguilar · Answer

undefined The sample of aluminum weighs 2.7 kg.