The complete combustion of 1 mole of pentane, #C_5H_12#, will require how many moles of oxygen, #O_2#?
In order to accomplish this, we must first write the chemical equation for the reaction using the standard formula for a combustion reaction involving hydrocarbons:
Thus
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One mole of pentane, C3H2O₂, will require 8.5 moles of oxygen, O₂, to burn completely.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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