The combustion of propane (#C_3H_8#) produces 248 of energy per mole of propane burned. How much heat energy will be released when 1 000 L of propane are burned at STP?
Approx......
The following equation can be used to illustrate propane combustion:
Your question does not even mention UNITS. I took the heat of combustion values from this website.
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To find the amount of heat energy released when 1,000 L of propane are burned at STP, we need to convert the volume of propane to moles using the ideal gas law, then use the given energy release per mole to calculate the total energy released.
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Convert 1,000 L of propane to moles using the ideal gas law: (PV = nRT).
- (P) = pressure = 1 atm (STP conditions)
- (V) = volume = 1,000 L
- (n) = moles (unknown)
- (R) = ideal gas constant = 0.0821 L·atm/mol·K
- (T) = temperature = 273 K (STP conditions)
- Solve for (n).
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Once you have the number of moles, multiply it by the energy release per mole of propane burned (248 kJ/mol) to find the total energy released.
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Perform the calculations.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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