# The base of a triangular pyramid is a triangle with corners at #(2 ,6 )#, #(5 ,3 )#, and #(8 ,2 )#. If the pyramid has a height of #2 #, what is the pyramid's volume?

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The volume of the triangular pyramid can be calculated using the formula: Volume = (1/3) * Area of base * Height

First, find the area of the base triangle using the coordinates provided using the formula for the area of a triangle given its vertices.

Then, substitute the found area and the given height into the volume formula to find the volume of the pyramid.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- A pyramid has a base in the shape of a rhombus and a peak directly above the base's center. The pyramid's height is #8 #, its base has sides of length #9 #, and its base has a corner with an angle of #(2 pi)/3 #. What is the pyramid's surface area?
- The base of a triangular pyramid is a triangle with corners at #(5 ,8 )#, #(2 ,3 )#, and #(9 ,4 )#. If the pyramid has a height of #4 #, what is the pyramid's volume?
- How do you find the area of a rhombus given the diagonals?
- If the radius of a circle is tripled, how does the circumference change?
- A ring torus has an ellipse of semi axes a and b as cross section. The radius to the axis of the torus from its center is c. Without integration for solid of revolution, how do you prove that the volume is #2pi^2abc#?

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