The base of a triangular pyramid is a triangle with corners at #(2 ,6 )#, #(5 ,3 )#, and #(8 ,2 )#. If the pyramid has a height of #2 #, what is the pyramid's volume?

Answer 1

#color(crimson)("Volume of pyramid " V_p = (1/3) * A_t * h = 28 " cub. units"#

#A (2,6), B (5,3), C (8,2), h = 2#
#"Area of base triangle " A-T = |(1/2)( x_1 (y_2-y_3) + x_2 (y_3 - y_1) + x_3 (y_1 - y_2))|#
#A_t = |(1/2) (2 (3-2) + 5 (2-6) + 8 (6 - 3))| = 42#
#color(crimson)("Volume of pyramid " V_p = (1/3) * A_t * h = (1/3) * 42 * 2 = 28#
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Answer 2

The volume of the triangular pyramid can be calculated using the formula: Volume = (1/3) * Area of base * Height

First, find the area of the base triangle using the coordinates provided using the formula for the area of a triangle given its vertices.

Then, substitute the found area and the given height into the volume formula to find the volume of the pyramid.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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