The base of a triangular pyramid is a triangle with corners at #(2 ,5 )#, #(1 ,6 )#, and #(2 ,8 )#. If the pyramid has a height of #4 #, what is the pyramid's volume?

Answer 1

Volume of a pyramid is # 2 # cubic unit.

Volume of a pyramid is #1/3*#base area #*#hight.
#(x_1,y_1)=(2,5) ,(x_2,y_2)=(1,6),(x_3,y_3)=(2,8) , h=4#
Area of Triangle is #A_b = |1/2(x1(y2−y3)+x2(y3−y1)+x3(y1−y2))|#
#A_b = |1/2(2(6−8)+1(8−5)+2(5−6))|# or
#A_b = |1/2(-4+3-2)| = | -3/2| =3/2#sq.unit
Volume of a pyramid is #1/3*A_b*h = 1/cancel3 *cancel3/2*4 = 2 # cubic.unit [Ans]
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Answer 2

To find the volume of the triangular pyramid, we use the formula:

[ V = \frac{1}{3} \times \text{base area} \times \text{height} ]

First, we need to calculate the area of the base triangle using the coordinates given for its vertices. We can use the formula for the area of a triangle given its vertices.

Let's denote the vertices as ( A(2, 5) ), ( B(1, 6) ), and ( C(2, 8) ).

The formula for the area of a triangle with vertices ( (x_1, y_1) ), ( (x_2, y_2) ), and ( (x_3, y_3) ) is:

[ \text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| ]

Let's calculate the area of the base triangle using the given coordinates:

[ \text{Area} = \frac{1}{2} |2(6 - 8) + 1(8 - 5) + 2(5 - 6)| ]

[ \text{Area} = \frac{1}{2} |-4 + 3 - 2| ]

[ \text{Area} = \frac{1}{2} \times 3 ]

[ \text{Area} = \frac{3}{2} ]

Now, we have the area of the base triangle and the height of the pyramid. Let's substitute these values into the formula for the volume of the pyramid:

[ V = \frac{1}{3} \times \frac{3}{2} \times 4 ]

[ V = \frac{1}{3} \times \frac{3}{2} \times 4 ]

[ V = \frac{1}{3} \times 6 \times 4 ]

[ V = 8 ]

Therefore, the volume of the triangular pyramid is 8 cubic units.

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Answer 3

The volume of a triangular pyramid can be calculated using the formula:

[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} ]

First, we need to find the area of the base triangle using the coordinates provided. We can use the formula for the area of a triangle given its vertices.

Then, we can substitute the base area and the height into the volume formula to find the volume of the pyramid.

Given the coordinates of the base triangle as (2,5), (1,6), and (2,8), the base triangle's area is 3 square units.

Substituting the base area and height into the volume formula:

[ V = \frac{1}{3} \times 3 \times 4 = 4 ]

So, the volume of the triangular pyramid is 4 cubic units.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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