The average of 5 numbers is 6. The average of 3 of them is 8. What is the average of the remaining two?

Answer 1

#3#

Given that the average of #5# numbers is #6#, their sum is #5xx6=30#.
Given that the average of the #3# selected numbers is #8#, their sum is #3xx8 = 24#.
So the remaining two numbers add up to #30-24 = 6# and their average is #6/2 = 3#
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Answer 2

To find the average of the remaining two numbers, you can use the following steps:

  1. Multiply the average of the 5 numbers by 5 to find the total sum of all 5 numbers.
  2. Multiply the average of the 3 numbers by 3 to find the total sum of those 3 numbers.
  3. Subtract the total sum of the 3 numbers from the total sum of all 5 numbers to find the total sum of the remaining two numbers.
  4. Divide the total sum of the remaining two numbers by 2 (since there are 2 numbers) to find their average.

So, the calculation would be:

Average of remaining two numbers = (\frac{(5 \times 6) - (3 \times 8)}{2})

Solving this equation:

Average of remaining two numbers = (\frac{(30) - (24)}{2})

Average of remaining two numbers = (\frac{6}{2})

Average of remaining two numbers = 3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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