# The atomic mass of fictitious element X is 51.70 amu. If element X consists of two isotopes that have mass numbers of 50 and 52, what is the approximate % natural abundance of each isotope?

% abundance of isotope with mass 50: 15%

% abundance of isotope with mass 52: 85%

Write the equation for relative atomic mass in terms of x (with x being one isotope's mass) and solve for x:

Find the value of y using x:

So % abundance for the isotope with mass number 50 is 15%, and the % abundance for the isotope with mass number 52 is 85%.

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The weighted average atomic mass can be calculated as follows: [51.70 = (50 \times x + 52 \times (100 - x)) / 100] Solving this equation yields: [x = \frac{52 - 51.70}{52 - 50}] [x \approx \frac{0.30}{2}] [x \approx 0.15] Therefore, the approximate % natural abundance of the isotope with mass number 50 is 15%, and the approximate % natural abundance of the isotope with mass number 52 is 85%.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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