# The area of a triangle is 16 more than the base. If the height is 6, what is the length of the base?

The length of the base is 8

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Let's denote the base of the triangle as ( b ) and the area as ( A ). The formula for the area (( A )) of a triangle is given by:

[ A = \frac{1}{2} \times \text{base} \times \text{height} ]

Given that the height (( h )) is 6, we have:

[ A = \frac{1}{2} \times b \times 6 = 3b ]

According to the problem, the area is 16 more than the base, so we can write this as:

[ A = b + 16 ]

Now, equating the two expressions for ( A ), we get:

[ 3b = b + 16 ]

Solving for ( b ):

[ 3b - b = 16 ] [ 2b = 16 ] [ b = \frac{16}{2} = 8 ]

So, the length of the base of the triangle is 8 units.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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