The area of a trapezoid is equal to half of the product of the height and sum of the bases. How do you rewrite the expression isolating one of the bases?

Answer 1
Since the area of the trapezium is #A = (1/2) h (a + b) = h(a + b)/2# where #a# & #b# are the two bases.

All you have to do is solve for either a or b:

#a + b = 2*(A/h)=> a = 2*(A/h) - b#

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Answer 2

To isolate one of the bases in the given expression, we can rearrange the formula for the area of a trapezoid. The formula for the area of a trapezoid is:

[ A = \frac{1}{2}h(b_1 + b_2) ]

Where:

  • ( A ) is the area of the trapezoid,
  • ( h ) is the height of the trapezoid,
  • ( b_1 ) is one base of the trapezoid, and
  • ( b_2 ) is the other base of the trapezoid.

To isolate ( b_1 ), we can start by multiplying both sides of the equation by 2 to get rid of the fraction:

[ 2A = h(b_1 + b_2) ]

Next, divide both sides of the equation by ( h ) to isolate the term containing ( b_1 ):

[ \frac{2A}{h} = b_1 + b_2 ]

Finally, to isolate ( b_1 ), subtract ( b_2 ) from both sides of the equation:

[ b_1 = \frac{2A}{h} - b_2 ]

So, the expression isolating one of the bases (( b_1 )) is ( b_1 = \frac{2A}{h} - b_2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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