# The area of a rectangle is 45 square cm. If the length is 4cm greater than the width, what are the dimension of the rectangle?

The length & width of rectangle are

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Let's denote the width of the rectangle as ( w ) cm. Since the length is 4 cm greater than the width, the length can be represented as ( w + 4 ) cm. The area of a rectangle is given by the formula:

[ \text{Area} = \text{length} \times \text{width} ]

Given that the area is 45 square cm, we can set up the equation:

[ w(w + 4) = 45 ]

Expanding the equation:

[ w^2 + 4w = 45 ]

Rearranging terms to form a quadratic equation:

[ w^2 + 4w - 45 = 0 ]

Now, we can factorize the quadratic equation or use the quadratic formula to solve for ( w ). After finding the value of ( w ), we can then find the length of the rectangle by adding 4 to ( w ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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