The amount of energy needed to heat 2.00 g of carbon from 50.0°C to 80.0°C is 42.6 J. The specific heat capacity of this sample of carbon is ?

Answer 1

Carbon has a specific heat of 0.710 J/g * C.

With the information at your disposal, you can calculate the specific heat of carbon by using

#q = m * c * DeltaT#, where
#q# - the amount of heat needed - in your case 42.6 J; #m# - the mass of the sample - in your case 2.00 g; #c# - the specific heat of carbon; #DeltaT# - the difference between the final and the initial temperature - in your case #80^@"C"# and #50^@"C"#;

Enter all of the data into the equation now.

#q = m * c * DeltaT => c = q/(m * DeltaT)#
#c = "42.6 J"/("2.00 g" * (80.0-50.0)^@"C") = 0.710 "J"/("g" * ^@"C")#
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Answer 2

To find the specific heat capacity of carbon, use the formula:

( q = mcΔT )

Where:

  • ( q ) is the amount of heat energy (42.6 J in this case)
  • ( m ) is the mass of the substance (2.00 g)
  • ( c ) is the specific heat capacity (what we're trying to find)
  • ( ΔT ) is the change in temperature (80.0°C - 50.0°C = 30.0°C)

Rearranging the formula to solve for ( c ):

( c = \frac{q}{mΔT} )

Plug in the values:

( c = \frac{42.6 , \text{J}}{2.00 , \text{g} \times 30.0 , \text{°C}} )

( c = \frac{42.6 , \text{J}}{60.0 , \text{g} \cdot \text{°C}} )

( c = 0.71 , \text{J/g°C} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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