The amount of energy needed to heat 2.00 g of carbon from 50.0°C to 80.0°C is 42.6 J. The specific heat capacity of this sample of carbon is ?
Carbon has a specific heat of 0.710 J/g * C.
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To find the specific heat capacity of carbon, use the formula:
( q = mcΔT )
Where:
- ( q ) is the amount of heat energy (42.6 J in this case)
- ( m ) is the mass of the substance (2.00 g)
- ( c ) is the specific heat capacity (what we're trying to find)
- ( ΔT ) is the change in temperature (80.0°C - 50.0°C = 30.0°C)
Rearranging the formula to solve for ( c ):
( c = \frac{q}{mΔT} )
Plug in the values:
( c = \frac{42.6 , \text{J}}{2.00 , \text{g} \times 30.0 , \text{°C}} )
( c = \frac{42.6 , \text{J}}{60.0 , \text{g} \cdot \text{°C}} )
( c = 0.71 , \text{J/g°C} )
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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