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The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of the gas?

Answer 1

Owen Ambrose

The pressure of the gas also increases by a factor of #4#.

We can make use of Gay-Lussac's Law because the volume is constant:

#P_1/T_1 = P_2/T_2#

Given that the problem indicates that the gas's temperature has increased by a factor of 4, we can substitute:

#T_2 = 4T_1#

Now, use this substitution to find #P_2# in terms of #P_1#.

#P_1/T_1 = P_2/T_2#

#P_1/T_1 = P_2/(4T_1) color(white)"XXXX"# substitute #4T_1# for #T_2#

#4P_1 = P_2 color(white)"XXXXX"# multiply both sides by #4T_1#

This means that #P_2# is #4# times #P_1#, so we can say that when the temperature of a gas increases by a factor of #4#, the pressure of the gas also increases by a factor of #4#.

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Answer 2

Ellie Andrews

The pressure of the gas will also increase four times.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.