Suppose y varies inversely with x, how do you write an equation for the inverse variation if y = 8 when x = 1/2?

Answer 1
Since it is an inverse variation it can be represented as: # color(red)(y) = color(blue)(k/color(red)(x# , where #color(blue)(k# represents the constant term , #color(red)(x and y)# are the variables.
Values for the variables are: #y=8# and #x=1/2#
substituting these values : # color(red)(y) = color(blue)(k/color(red)(x# # color(red)(y.x) = color(blue)(k#
# 1/2 . 8 = color(blue)(k) # we get the constant as # color(blue)k = 4#
# color(red)(y) = color(blue)(4/color(red)(x#
# color(red)(x.y) = color(blue)(4#, represents the inverse variation in which constant is #4#.
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Answer 2

The equation for the inverse variation is y = k/x, where k is the constant of variation. To find the value of k, substitute the given values of y and x into the equation and solve for k. In this case, when y = 8 and x = 1/2, the equation becomes 8 = k/(1/2). Simplifying, we get 8 = 2k. Solving for k, we find k = 4. Therefore, the equation for the inverse variation is y = 4/x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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