Suppose that 11 inches of wire costs 44 cents. At the same rate, how much (in cents) will 28 inches of wire cost?

Question

Savannah Anderson · Accepted Answer

See a solution process below:

Let's call the amount the 28 inches of wire will cost: #c# We can then write and solve for #c#: #(44" cents")/(11" in") = c/(28" in")# #color(red)(28" in") xx (44" cents")/(11" in") = color(red)(28" in") xx c/(28" in")# #color(red)(28color(black)(cancel(color(red)(" in")))) xx (44" cents")/(11color(red)(cancel(color(black)(" in")))) = cancel(color(red)(28" in")) xx c/color(red)(cancel(color(black)((28" in"))# #(28 xx 44" cents")/11 = c# #(28 xx color(red)(cancel(color(black)(44)))4" cents")/color(red)(cancel(color(black)(11))) = c# #28 xx 4" cents" = c# #112 = c# #c = 112# The cost of 28 inches of wire is 112 cents.

Ethan Adkins · Answer

undefined To find the cost of 28 inches of wire at the same rate, you can set up a proportion:

11 inches is to 44 cents as 28 inches is to x cents.

(11 / 44) = (28 / x)

Cross-multiply:

11x = 44 * 28

Solve for x:

x = (44 * 28) / 11

x = 112 cents

So, 28 inches of wire will cost 112 cents.