Suppose a car sitting on a hydraulic lift exerts a downward force of 1,750 N on a piston with an area of 0.6m^3. How much pressure does the car exert on the piston?

Answer 1

Pressure is defined as force per unit area, which in this case works out to be 2.917 kPa

A force of one newton applied over one square meter equals one pascal of pressure.

So, for a 1750 N force applied to 0.6 #m^3#, we find
#P=F/A# = #(1750N)/(0.6 m^3)# = 2917 Pa or 2.917 kPa
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Answer 2

The pressure exerted by the car on the piston is 2,917 Pa (Pascals).

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Answer 3

To find the pressure exerted by the car on the piston, we use the formula:

Pressure = Force / Area

Substitute the given values:

Pressure = 1750 N / 0.6 m^2

Pressure ≈ 2916.67 Pascal (Pa)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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