State the x and y intercept: y = -8/9x -16 ?

Answer 1

#y#-intercept #= -16#
#x#-intercept #= -18#

Compare the equation to

#y= mx +c#

Where

Hence,

#c= -16#
i.e the #y#-intercept is #-16#.
At the #x#-intercept, #y=0#. Therefore, let #y=0#.
#y= -8/9x -16#
#0= -8/9x -16#
#8/9x= -16#
Divide both sides of the 'equal to' sign by #8/9#
#x= -18#
Hence, the #x#-intercept is #-18#.
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Answer 2

The x-intercept is (18, 0) and the y-intercept is (0, -16).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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