Specific gravity of HCl is 1.08. what is its Molarity???

Question

Caleb Adams · Accepted Answer

Here's what I got.

Prior to proceeding, ensure that you comprehend the meaning of specific gravity. In most cases, specific gravity is defined as the ratio of a given substance's density to that of a reference substance at the same temperature; in most cases, this reference substance is water. #color(blue)("SG" = rho_"substance"/rho_"water")# Since no mention of temperature was made, you can assume the density of water to be equal to #"1.00 g/mL"#. In this case, the specific gravity of hydrochloric acid indicates how much a given hydrochloric acid solution weighs in relation to water. More precisely, your hydrochloric acid solution's density will be equivalent to #"SG" = rho_"HCl"/rho_"water" implies rho_"HCl" = "SG" xx rho_"water"# #rho_"HCl" = 1.08 xx "1.00 g/mL" = "1.08 g/mL"# Now that you are aware of the solution's density, you can use this information to determine the molarity of the solution by taking a sample and calculating the moles of hydrochloric acid it contains. You can now find the percent concentration of hydrochloric acid by mass in this solution, which is necessary. Percentage of concentration: https://tutor.hix.ai A hydrochloric acid solution that has a density of #"1.08 g/mL"# (I assumed room temperature) is about #17%"w/w"# #"HCl"#, that is, you get #"17 g"# of hydrochloric acid for every #"100.0g "# of solution. To make the calculations easier, pick a #"1.00-L"# sample of this solution. Use its density to find its mass #1.00color(red)(cancel(color(black)("L"))) * (1000color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.08 g"/(1color(red)(cancel(color(black)("mL")))) = "1080 g"# Next, calculate the amount of hydrochloric acid it contains using its mass percentage concentration. #1080color(red)(cancel(color(black)("g solution"))) * "17 g HCl"/(100color(red)(cancel(color(black)("g solution")))) = "183.6 g"# Next, calculate the number of moles of hydrochloric acid in these many grams using the molar mass of hydrochloric acid. #183.6color(red)(cancel(color(black)("g"))) * "1 mole HCl"/(36.46color(red)(cancel(color(black)("g")))) = "5.0357 moles HCl"# Since molarity is defined as moles of solute, which in your case is hydrochloric acid, divided by liters of solution, and you picked an initial sample of #"1.00-L"#, it follows that the solution's molarity will be #color(blue)(c = n/V)# #c = "5.0357 moles"/"1.00 L" = "5.0357 M"# The answer, rounded to three sig figs, will be the number of sig figs you have for the specific gravity of the solution. #c = color(green)("5.04 M")#

Caleb Adams · Answer

undefined To find the molarity of HCl, you can use the equation:

Molarity (M) = (Specific gravity * 1000) / (36.46 g/mol)

Given that the specific gravity of HCl is 1.08, plugging this into the equation:

Molarity (M) = (1.08 * 1000) / (36.46 g/mol)

Molarity ≈ 29.61 M