# Solve the following algebraic equation: #|2x^2-x|=2x^2-x+8#?

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To solve the equation |2x^2-x|=2x^2-x+8, we need to consider two cases: when the expression inside the absolute value is positive and when it is negative.

Case 1: 2x^2-x is positive: 2x^2-x = 2x^2-x+8 This simplifies to 0 = 8, which is not true. Therefore, there are no solutions in this case.

Case 2: 2x^2-x is negative: When 2x^2-x is negative, we need to change the sign of the expression inside the absolute value. -(2x^2-x) = 2x^2-x+8 This simplifies to -2x^2+x = 2x^2-x+8 Rearranging the terms, we get 4x^2 = 9 Taking the square root of both sides, we have x = ±√(9/4) Therefore, the solutions to the equation are x = -3/2 and x = 3/2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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