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Solve the equation #cos2x+sin^2x=4/9# to the nearest hundredth where #0lexle360^0#?

Answer 1

Anna Andrews

#x=48'11', 131'49', 228'11', 311'49'#

#cos2x+(sinx)^2=4/9#

#1-2(sinx)^2+(sinx)^2=4/9#

#1-(sinx)^2=4/9#

#(sinx)^2=5/9#

#sinx=+-(sqrt5)/3#

#x=48'11', 131'49', 228'11', 311'49'#

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Answer 2

Carter Anderson

To solve the equation ( \cos^2x + \sin^2x = \frac{4}{9} ) for ( 0 \leq x \leq 360^\circ ), you can use the Pythagorean identity ( \cos^2x + \sin^2x = 1 ) to simplify the equation. After rearranging terms, you'll find that ( 1 = \frac{4}{9} ), which is not true. Therefore, there are no solutions to the equation in the given range.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.