#(sin x)'=cos x, (cos x)'=-sin x, int sin x dx = -cos x + C, int cos x dx = sin x + C and e^(ix)=cos x + i sin x#. Are all these OK, if x is in degree mode?
correct.
Solution is correct.
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No, those statements are not entirely accurate if ( x ) is in degree mode. The derivatives and integrals you provided are correct for trigonometric functions when ( x ) is in radian mode. However, if ( x ) is in degree mode, the derivatives and integrals need to be adjusted accordingly. Here are the correct versions:
- ( \frac{d}{dx}(\sin x) = \cos x ) holds true regardless of whether ( x ) is in degree or radian mode.
- ( \frac{d}{dx}(\cos x) = -\sin x ) holds true regardless of whether ( x ) is in degree or radian mode.
- ( \int \sin x , dx = -\cos x + C ) holds true regardless of whether ( x ) is in degree or radian mode.
- ( \int \cos x , dx = \sin x + C ) holds true regardless of whether ( x ) is in degree or radian mode.
- ( e^{ix} = \cos x + i \sin x ) holds true only when ( x ) is in radian mode. If ( x ) is in degree mode, you need to convert degrees to radians before using this formula.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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