Sec #theta# -1#-:#sec #theta# =?

I understand sign conversions, but I think it should be one, sine 1/cos and -1/1/cos would subtract to 1? but my options are 1+cos, -2tan^2 sec csc, sin tan. With thetas respectively.

Answer 1

#color(green)(1-cos theta)#

#sec theta = 1 / cos theta#
#(sec theta - 1 ) /sec theta = ((1/cos theta) - 1) / (1/cos theta)#
#=> (1 - cos theta) / cancel(cos theta) / (1/cancelcos theta) = 1-cos theta#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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