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Sarah is 25 years older than her son Gavin. In ten years, Sarah will be twice Gavin age. How old are Sarah and Gavin?

Answer 1

Genesis Allen

Below.

Let Garvin's age be #=x# and Sarah's age #=x +25#

After #10# years

Garvin's age #= x + 10# Sarah's age #= 2(x +10) or x+ 35#

According to the question

#2 (x + 10 ) = x + 35#

#2x + 20 = x + 35#

#2x-x = 35-20#

#x = 15#

Therefore, Gavin's age is #15# years and Sarah's age is #40# years.

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Answer 2

Ethan Adkins

Sarah is 40 and Gavin is 15

Let (G+25) be Sarah's age and G be Gavin's age #S= G+25# #G+25=2(G+10)# #G=15# #S=40#

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Answer 3

Eva Abramson

Let's represent Gavin's current age as ( x ) years. Sarah is 25 years older than Gavin, so her current age is ( x + 25 ) years. In ten years, Gavin's age will be ( x + 10 ) years, and Sarah's age will be ( (x + 25) + 10 = x + 35 ) years. According to the given condition, Sarah will be twice Gavin's age in ten years:

[ x + 35 = 2(x + 10) ]

Solve for ( x ):

[ x + 35 = 2x + 20 ] [ 35 - 20 = 2x - x ] [ 15 = x ]

So, Gavin is currently 15 years old. Sarah is ( x + 25 = 15 + 25 = 40 ) years old.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.