(R + RCos (2,57 (20)) = 12), How to solve for R?

Answer 1

This solution is based on #cos(2.57xx20)#
#R~~7.390# to 3 decimal places
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#R=12/(1+cos(2.5720)) ~~6.003# to 3 decimal places

Given: #R+Rcos(2.57(20))=12#

Factor out the R giving

#R(1+cos(2.57(20))=12#
Divide both sides by #(1+cos(2.57(20))# giving
#R xx (1+cos(2.57(20)))/(1+cos(2.57(20))) =12/(1+cos(2.57(20))) #
But #(1+cos(2.57(20))) /(1+cos(2.57(20))) =1# giving
#R=12/(1+cos(2.57(20))) #
#R~~7.390# to 3 decimal places
This solution is based on #cos(2.57xx20)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Or, if you meant: #R=12/(1+cos(2.5720)) #
#R=6.003# to 3 decimal places
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Answer 2

To solve for R in the equation (R + R \cos(2.57 \times 20) = 12):

  1. Subtract (R \cos(2.57 \times 20)) from both sides.
  2. Factor out (R) from the left side.
  3. Divide both sides by the factor of (1 + \cos(2.57 \times 20)).
  4. Calculate the value of (R).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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