Points P(1,0), Q(8,0) and R(3,4) are the vertices of a triangle. What is the area of this triangle?
Use a Determinant as shown in this reference.
Create the determinant:
#A = +-1/2| (1, 0, 1), (8,0, 1), (3,4,1) |#
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To find the area of the triangle with vertices P(1,0), Q(8,0), and R(3,4), you can use the formula for the area of a triangle given its coordinates:
Area = 1/2 * |x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)|
Substituting the coordinates of the vertices: x1 = 1, y1 = 0 x2 = 8, y2 = 0 x3 = 3, y3 = 4
Area = 1/2 * |1(0 - 4) + 8(4 - 0) + 3(0 - 0)|
Area = 1/2 * |-16 + 32 + 0|
Area = 1/2 * |16|
Area = 1/2 * 16
Area = 8 square units
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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