Please solve q 96 ?

Answer 1

Sorry don't know how to put a diagram on but using your sketch...

In #Delta#BEC : #ChatBE=51^@# and #EhatCB=78^@# given, so #BhatEC=51^@# This makes it isosceles with BC=CE
In #Delta#BCD : #DhatBC=78^@# and #BhatCD=24^@# given, so #BhatDC=78^@# This makes it isosceles with BC=DC
From this working CE=DC making #Delta#DEC isosceles too with #DhatCE=54^@# so #ChatDE=ChatED=63^@#
As #BhatEC=51^@# then #BhatED=63-51=12^@#

Option 3

Hope you can follow this!

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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