Phosphoric acid is commonly supplied as an 85% solution. What mass of this solution would be required to prepare 600.0 mL of a 2.80 M phosphoric acid solution?

Answer 1

Olivia Anton

A total of 194 g of the 85% H3PO4 would be required.

The following conversions are necessary:

Mass of HPO₄ → mass of 85% HPO₄ → volume of diluted acid → moles of HPO₄

0.6000 L dil. acid × #("2.80 mol H"_3"PO"_4)/"1 L dil. acid" × ("98.00 g H"_3"PO"_4)/("1 mol H"_3"PO"_4)# ×

"85 g H"_3"PO"_4"/"100 g 85 % H"_3"PO"_4" = "194 g of 85 % H"_3"PO"_4"

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Answer 2

Peyton Adams

To prepare 600.0 mL of a 2.80 M phosphoric acid solution, you would need 134.15 grams of the 85% solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.