Pg 23, q36 How do I figure this out? thanks

Answer 1

#AC~~5.12#
#BD~~9.67#

We the following things:

  • #AB=DC=3.7#
  • #CB=AD=6.8#
  • #/_ABC=/_ADC=48#

We can use the cosine rule to find out #AC# and #BD#

#c^2=a^2+b^2-2bcosC#

#C=48#
#a=6.8#
#b=3.7#

#AC=c=sqrt(6.8^2+3.7^2-2(6.8*3.7)cos48)~~5.12#

Co-interior angles add up to #180^circ#.

So, #/_BAD=/_BCD=180-48=132#

Again, we can use the cosine rule, but replace #48# with #132#

#C=132#
#a=6.8#
#b=3.7#

#BD=c=sqrt(6.8^2+3.7^2-2(6.8*3.7)cos132)~~9.67#

#AC~~5.12#
#BD~~9.67#

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Answer 2

To assist you effectively, I would need more context about what material or textbook you're referring to. Without knowing the specific content of page 23 and question 36, it's challenging to provide guidance. Could you please provide more details or clarify the subject or topic of the question? This will enable me to offer you the appropriate assistance.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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