Payton colored a composite shape made up semicircles whose diameters are the sides of a square. The result is a shape given below. Find the area of the shaded region (Petals) in terms of x? Calculate the area using the dimension in 2nd figure?

Answer 1

Area #=8x^2(pi-2)#

The area of half a petal is given by

#(pi r^2)/4-r^2/2 = r^2/4(pi-2)#

See the attached figure:
in light blue is represented the circle's quarter #(pi r^2)/4#
in yellow is represented the triangle's area #r^2/2#
in red is represented the difference #(pi r^2)/4-r^2/2#

(Note: the halfed petal is rotated #45^@#)

so the four petals have an area of

#8 r^2/4(pi-2)= 2r^2(pi-2)# but #r = 2x# then

Area #=8x^2(pi-2)#

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Answer 2

To find the area of the shaded region (petals) in terms of ( x ), we first need to understand the composition of the shape.

The shaded region consists of four semicircles whose diameters are the sides of a square. Each semicircle has a radius equal to half the side length of the square. Therefore, the area of one semicircle is ( \frac{\pi}{2} \times \left(\frac{x}{2}\right)^2 ).

Since there are four identical semicircles, the total area of the shaded region is ( 4 \times \frac{\pi}{2} \times \left(\frac{x}{2}\right)^2 ).

Now, let's calculate the area using the dimensions provided in the second figure.

In the second figure, the side length of the square is ( x ). Therefore, the radius of each semicircle is ( \frac{x}{2} ).

Using the formula for the area of a semicircle (( \frac{\pi}{2} r^2 )), where ( r ) is the radius:

[ \text{Area of one semicircle} = \frac{\pi}{2} \times \left(\frac{x}{2}\right)^2 ]

[ = \frac{\pi}{2} \times \frac{x^2}{4} ]

[ = \frac{\pi x^2}{8} ]

Since there are four identical semicircles, the total area of the shaded region is:

[ \text{Total area} = 4 \times \frac{\pi x^2}{8} ]

[ = \frac{\pi x^2}{2} ]

So, the area of the shaded region (petals) in terms of ( x ) is ( \frac{\pi x^2}{2} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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