Part of the proceeds from a garage sale was $490 worth of $10 and $20 bills. lf there were 4 more $10 bills than $20 bills, how do you find the number of each denomination?

Question

Savannah Anderson · Accepted Answer

15 ($20 dollar bills) and 19 ($10 dollar bills).

If we let #x# be the number of $20 dollar bills then there are #x+4# $10 dollar bills. The equation of the problem is: #10(x+4)+20(x)=490# #10x+40+20x=490# #30x=450# #x=15# Then there are 15 $20 dollar bills and 19 $10 dollar bills.

Julia Adams · Answer

19 #$10# bills and 15 #$20# bills

Your equation: #20*x + 10*(4+x)=490# #20x+40+10x=490# #30x=450# #x=15# (x indicates number of #$20 bills). Since there are 4 more bills under #$10# category compared to the other, Your 10 dollar bills number is #=15+4=19#.

Isaiah Anthony · Answer

undefined Let x represent the number of $20 bills.
Then the number of $10 bills would be x + 4.

The total value of the $20 bills is 20x.
The total value of the $10 bills is 10(x + 4).

Since the total proceeds from the garage sale were $490, we can set up the equation:

20x + 10(x + 4) = 490

Solve for x:

20x + 10x + 40 = 490
30x + 40 = 490
30x = 450
x = 15

So, there were 15 $20 bills and 15 + 4 = 19 $10 bills.