Parker has quarters and dimes his piggy bank. He has 4 more dimes than quarters, and he a total of $7.05 in his bank. How many dimes and quarters does Parker have?

Answer 1

Parker has #19# quarters and #23# dimes.

Let Parker has #x# quarters #($0.25)#. Then he has #x+4# dimes #($0.10)#. So by given condition #x*0.25+(x+4)*0.10=7.05 or 0.25x+0.10x=7.05-0.40 or 0.35x = 6.65 or x=6.65/0.35=19 ; x+4=23# So Parker has #19# quarters and #23#dimes.[Ans]

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Answer 2

Isaiah Anthony

Let's represent the number of quarters Parker has as (q) and the number of dimes as (d).

Given:

(d = q + 4)
The total value of quarters and dimes is $7.05, or 705 cents.

We can set up the equation: (25q + 10d = 705)

Substitute the value of (d) from the first equation into the second equation: (25q + 10(q + 4) = 705)

Solve for (q): (25q + 10q + 40 = 705) (35q + 40 = 705) (35q = 665) (q = 19)

Now, substitute the value of (q) back into the first equation to find (d): (d = 19 + 4) (d = 23)

So, Parker has 19 quarters and 23 dimes.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.