One number is four times another. the larger number is also 87 more than the smaller number. How do you find the numbers?

Answer 1

29 and 116

#x# -- the number
#4x# -- this is 4 times that number
#87 + x# -- the value of the larger number is #87# more than the smaller number
#87 + x = 4x#
Solve for #x#...
#87 = 3x#
#29 = x#
The other number can be calculated by either adding #87# or multiplying #29# by #4#.
With adding #87#... #29 + 87 = 116#
With multiplying #29# by #4#... #29 \times 4 = 116#
The two numbers are #29# and #116#
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Answer 2

Let's call the smaller number ( x ) and the larger number ( y ).

According to the problem, we have two equations:

  1. ( y = 4x )
  2. ( y = x + 87 )

Substitute the value of ( y ) from the first equation into the second equation: ( 4x = x + 87 )

Now, solve for ( x ): ( 3x = 87 ) ( x = 29 )

Now, substitute the value of ( x ) back into the first equation to find ( y ): ( y = 4(29) ) ( y = 116 )

So, the smaller number is 29 and the larger number is 116.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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