One afternoon, Dave cast a 5-foot shadow. At the same time, his house cast a 20-foot shadow. If Dave is 5 feet 9 inches tall, how tall is his house?
His house is
This is because shadows are formed by sun, who in comparison is at a huge distance. For example, if such shadows are formed by a beam of light from a lamp post, the same may not be in same proportion.
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Dave's height is 5 feet 9 inches, which is equivalent to 5.75 feet. Using proportions, we can find the height of his house:
( \frac{\text{Height of Dave's house}}{\text{Length of Dave's shadow}} = \frac{\text{Height of Dave}}{\text{Length of Dave's shadow}} )
( \frac{\text{Height of Dave's house}}{20} = \frac{5.75}{5} )
( \text{Height of Dave's house} = \frac{20 \times 5.75}{5} )
( \text{Height of Dave's house} = 23 ) feet
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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