# One afternoon, Dave cast a 5-foot shadow. At the same time, his house cast a 20-foot shadow. If Dave is 5 feet 9 inches tall, how tall is his house?

His house is

This is because shadows are formed by sun, who in comparison is at a huge distance. For example, if such shadows are formed by a beam of light from a lamp post, the same may not be in same proportion.

By signing up, you agree to our Terms of Service and Privacy Policy

Dave's height is 5 feet 9 inches, which is equivalent to 5.75 feet. Using proportions, we can find the height of his house:

( \frac{\text{Height of Dave's house}}{\text{Length of Dave's shadow}} = \frac{\text{Height of Dave}}{\text{Length of Dave's shadow}} )

( \frac{\text{Height of Dave's house}}{20} = \frac{5.75}{5} )

( \text{Height of Dave's house} = \frac{20 \times 5.75}{5} )

( \text{Height of Dave's house} = 23 ) feet

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7