# On the figure given show that #bar(OC)# is #sqrt(2)#?

WOW...I finally got it...although it seems too easy...and probably it is not the way you wanted it!

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To show that the length of bar OC is √2, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In the given figure, OC represents the hypotenuse of a right triangle OAC. Let's denote OA as 'a' and AC as 'a'. Then, using the Pythagorean theorem:

OC² = OA² + AC²

Substituting the values:

OC² = a² + a² OC² = 2a²

Now, taking the square root of both sides to find the length of OC:

OC = √(2a²)

Since 'a' represents the length of a side of the square, we have:

a = 1 (assuming the side length of the square is 1)

OC = √(2 * 1²) OC = √2

Thus, the length of bar OC is √2.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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