On a spinner, #P(3) = 2/5# and the #P(4) = 3/8#, what is the probability of getting 3 or 4?

Answer 1

#2/5+3/8=16/40+15/40=31/40#

Let's think about a regular, fair die for a second. There are 6 sides and so the probability of rolling a 1 is #1/6#. The probability of rolling a 2 is also #1/6#. The probability of rolling a 1 or a 2, therefore, is the probabilities of each one occurring added to the other:

#1/6+1/6=2/6=1/3#

And so with the spinner, we do the same thing - we add the probabilities together:

#2/5+3/8=16/40+15/40=31/40#

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Answer 2

Anthony Amato

To find the probability of getting a 3 or a 4 on the spinner, we simply add the probabilities of getting each outcome.

P(3 or 4) = P(3) + P(4)

Given that P(3) = 2/5 and P(4) = 3/8, we can substitute these values into the equation:

P(3 or 4) = 2/5 + 3/8

To add these fractions, we need a common denominator, which is 40. So, we convert the fractions:

2/5 = 16/40 3/8 = 15/40

Now, we can add them:

P(3 or 4) = 16/40 + 15/40 = 31/40

Therefore, the probability of getting a 3 or a 4 on the spinner is 31/40.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.