Home > Algebra > Inequalities with Addition and Subtraction

On a number line how do you graph x+3 < -1?

Answer 1

Eva Abramson

Refer to the explanation.

Solve and graph:

#x+3<-1#

Subtract #3# from both sides.

#x<-1-3#

Simplify.

#x<-4#

To graph this on a number line, draw an open circle above the #-4# and shade in the part of the number line to the left of #-4#.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eli Assouline

To graph the inequality ( x + 3 < -1 ) on a number line, follow these steps:

Start by drawing a number line with a mark for each integer.
Locate the point where the expression ( x + 3 ) equals -1. Subtract 3 from -1 to find that ( x = -4 ).
Since the inequality is strict (less than), use an open circle (○) at the point -4 on the number line to represent that -4 is not included in the solution set.
Shade the region to the left of the open circle to represent all the values of x that make the inequality true.

The graph should show an open circle at -4 with shading to the left indicating all values of x less than -4.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

On a number line how do you graph x+3 &lt; -1?

On a number line how do you graph x+3 < -1?